From ruby-math-admin@ruby-lang.org Thu Jul 17 09:17:42 2003 Received: from kankan.nagaokaut.ac.jp (kankan.nagaokaut.ac.jp [133.44.2.24]) by blade.nagaokaut.ac.jp (8.12.3+3.5Wbeta/8.12.6/Debian-8) with ESMTP id h6H0HgXh010056; Thu, 17 Jul 2003 09:17:42 +0900 Received: from funfun.nagaokaut.ac.jp (funfun.nagaokaut.ac.jp [133.44.2.201]) by kankan.nagaokaut.ac.jp (Postfix) with SMTP id B9E5D5894; Thu, 17 Jul 2003 09:22:39 +0900 (JST) Received: from helium.ruby-lang.org (helium.ruby-lang.org [210.251.121.214]) by voscc.nagaokaut.ac.jp (Postfix) with ESMTP id CC04B63003F; Thu, 17 Jul 2003 09:22:37 +0900 (JST) Received: from hoyogw.ruby-lang.org (localhost [127.0.0.1]) by helium.ruby-lang.org (Postfix) with ESMTP id 0C7096D; Thu, 17 Jul 2003 09:22:36 +0900 (JST) Date: Thu, 17 Jul 2003 09:23:36 +0900 From: matz@ruby-lang.org (Yukihiro Matsumoto) Reply-To: ruby-math@ruby-lang.org Subject: [ruby-math:00899] Re: defining ternary operator To: ruby-math@ruby-lang.org Message-Id: <1058401416.954568.28437.nullmailer@picachu.netlab.jp> In-Reply-To: Masahide Kikkawa's message of "Wed, 16 Jul 2003 15:04:16 -0500" References: <20030615.232143.74757495.GEC01122@nifty.ne.jp> X-ML-Name: ruby-math X-Mail-Count: 00899 X-MLServer: fml [fml 4.0.3 release (20011202/4.0.3)]; post only (only members can post) X-ML-Info: If you have a question, send e-mail with the body "help" (without quotes) to the address ruby-math-ctl@ruby-lang.org; help= X-Mailer: cmail 2.62 on GNU Emacs 21.3.2 / Mule 5.0 (SAKAKI) User-Agent: SEMI/1.14.4 (Hosorogi) FLIM/1.14.5 (Demachiyanagi) APEL/10.5 Emacs/21.3 (i386-pc-linux-gnu) MULE/5.0 (SAKAKI) Mime-Version: 1.0 (generated by SEMI 1.14.4 - "Hosorogi") Content-Type: text/plain; charset=ISO-2022-JP Precedence: bulk Lines: 8 List-Id: ruby-math.ruby-lang.org List-Software: fml [fml 4.0.3 release (20011202/4.0.3)] List-Post: List-Owner: List-Help: List-Unsubscribe: X-Virus-Scanned: by AMaViS perl-10 まつもと ゆきひろです In message "[ruby-math:00898] defining ternary operator" on 03/07/16, Masahide Kikkawa writes: | rubyの ternary operator a ? b : c を定義するにはどうやったら良いのでしょう? できません。一部の「制御構造的演算子」は再定義できません。