Hello!

On Wed, Feb 04, 2004 at 08:52:43AM +0900, Guillaume Marcais wrote:
> Is there a specific reason of why you want to do that?
> 
> > Thanks Lyle for the quick reply. What I wanted to do was
> > something I could do in C like:
> > 
> >     RFLOAT(foo)->value = RFLOAT(x)->value;
> > 
> > I thought if Ruby could do this ad hoc for Float objects.

Yes, a lazy way to port this kind of behaviour:

    int foo;
    Bar *b = new Bar(&foo);
    for (int i; i < 10; i++)
     {
        foo = i;
        b->collect();
     }
     
    b->dump();

ANW, I found how to accomplish such a thing, but it would
be easier if Ruby supported it by nature.

Regards,
-- 
University of Athens			I bet the human brain 
Physics Department				is a kludge --Marvin Minsky