> M> k=0; ("A".."k").each{|x|k+=1}; k
> M> I expected 11, I got 26. Why is that?
>  why 11 ?
>  You have 11 with ("A".."K")

Oops, nearly a brain fart. That's not 11 I wanted to write, it's 37, that
is, 11+26.  Precisely, like 'A'..'Z' followed by 'a'..'k'. 

Now that I think of it, I understand why it gives "A".."Z", and why it
makes sense to. I'm only *really* awake starting with the end of the
afternoon :-) 

matju