Hi,

In message "Re: defout vs stdout"
    on 03/03/25, ahoward <ahoward / fsl.noaa.gov> writes:

|this is what i *thought* was meant by 'in-place', but many, many, threads have
|discussed $defout simply as a means of redirecting/dupping/etc the stdout of a
|process.
|
|is this an abuse then?

No.  $defout is a "default output of print/printf etc." and -i replace
the input file by $defout output (after making backup).  Does this
make sense?

							matz.