```
-----Messaggio originale-----
Da: Ja xv [mailto:jeniferjblack / hotmail.com]
Inviato: venerd11 novembre 2011 23:47
A: ruby-talk ML
Oggetto: calculating the prime factors of a very large number

question:
How would you write the code to find the prime factors of a very large
number?

I think one of the factors is small (ie) less than 1000 the code I have
written is:

print ' please enter num: '
num_one=gets.chomp.to_i
data = []
for x in (3..1000)
if   x%2!=0 then
a = (x+1)/2
for i in (2..a)
if (x%i!=0)then
if i==a then
if num_one% x==x then
num_one/x=y
data <<x
print x
print y
end
end
end

end
end
end

#the large numbers given num_one and num_two are both odd

num_one =
2107223609161105668976918317066561183910066035018968816252689949383528072901
7620910006683962065747474746709582322870618924665901484145427690586656845288
5184216817156736191122897117017204303913460454982456911293788381172179723704
4148971768379805180467794140878622058164489327264965270826072588392667925176
1833970410399147125916239687836131680486047711823435095777510281209932021075
8552707199048382382442649785375300332462260192629013022593323262011189565838
1739364984572332984356941312726357025505146283362673660738098896234205957499
7647316022718247287419422282235170644994619557795227339530396253222625063056
535813277

num_2 =
1809802298989276148958523994291171014652756057654232959690054414244110865190
4796522651752720928703424386982425423665426965077873850560389609781060355447
2797099957268999735645451862866599047554310106053073400016747052276933651693
2019944930453138611240487320778888202694152570407283502487489178308645124685
9794179361352738425027303207459758129563202191968841767084921880243978706845
0273090792416213728427471241952690295098911214297345232764670796463979696711
4525312948298707481973552067527543489907959715400906153465279228882001220301
2543866955452538172728992749602975245656098892700288816953569845819775152239
0933149786001

##I need help in writing the code, am I on the right track?

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