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On Thu, Sep 8, 2011 at 8:54 PM, Michael Kohl <citizen428 / gmail.com> wrote:

> On Wed, Sep 7, 2011 at 12:47 AM, Intransition <transfire / gmail.com> wrote:
> > Is there a method out there already that does anything like this?
> >
> >    [0,1,2,3,4].group(0..-2, -1)  #[[0,1,2,3]. [4]]
> >    [0,1,2,3,4].group(0, 2..3, 4..-1)  #[[0], [2,3], [4]]
>
> I guess I would just do something like this:
>
> yes it does works vey well, nice code snippet.

> class Array
>  def group(*ranges)
>     ranges.map { |r| values_at(r) }
>   end
> end
>
> >> [0,1,2,3,4].group(0..-2, -1)
> [[0, 1, 2, 3], [4]]
> >> [0,1,2,3,4].group(0, 2..3, 4..-1)  #[[0], [2,3], [4]]
>

can we have something so that if we pass array variable name instead of
actual elements of array like  0, 2..3, 4..-1
i mean if range0, 2..3, 4..-1], array 0,1,2,3,4]
then array.group(range), should give same o/p

[[0], [2, 3], [4]]
>
>


-- 
Regards,
Rahul Patil

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