Joshua S. wrote in post #995421:
> Not surprisingly, it's extremely quicker to convert to a string and
> match a regular expression.
>
>       user     system      total        real
> spf  :  1.560000   0.000000   1.560000 (  1.557252)
> *100 :  0.320000   0.000000   0.320000 (  0.322573)
> *.01 :  0.350000   0.000000   0.350000 (  0.343289)
> regex:  0.000000   0.000000   0.000000 (  0.000019)

You should be suspicious of a result which indicates it's 5 orders of 
magnitude faster.

>   r.report('regex:') {
>     f4 = float.to_s.match(/(^-?\d+(\.\d{1,2})?)/)[1].to_f
>   }

Ahem, you forgot the "times.times do...end" loop in the benchmark :-)

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