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Robert Klemme:

> You can either do

> x.sort_by {|let,dig| [dig, let]}

> or, if you don't want to create all those temporary arrays

> x.sort {|(la,da),(lb,db)| da == db ? la <=> lb : da <=> db}
> x.sort {|(la,da),(lb,db)| c = da <=> db; c == 0 ? la <=> lb : c}

Or use #nonzero? and #<=> chaining like this:

x.sort { |(la, da), (lb, db)| (da <=> db).nonzero? or la <=> lb }

Piotr Szotkowski
-- 
Language designers in general: You are IN THE WAY. Go here:
http://rebol.com/oneliners.html then do us all a favor and don”Ēt
resist the urge to fall on that wakizashi when your shame overcomes you.
                                                             [Jeff Bone]




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