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Help
Subject:
Re: name = upload['datafile'].original_filename
From:
Abder-Rahman Ali
<abder.rahman.ali gmail.com>
Date: Mon, 20 Sep 2010 21:42:00 +0900
References:
370095
370102
In-reply-to:
370102
Thanks a lot @Brian for this nice clarification. -- Posted via
http://www.ruby-forum.com/.