On May 9, 12:28=A0pm, Robert Klemme <shortcut... / googlemail.com> wrote:
> On 05/08/2010 09:20 PM, Viorel wrote:
>
>
>
>
>
> > On May 8, 5:28 pm, Robert Klemme <shortcut... / googlemail.com> wrote:
> >> On 08.05.2010 12:12, Viorel wrote:
>
> >>> I have some names like aaxxbbyy where xx is '01'..'10' and yy is also
> >>> '01'..'10'. I think there is a simple, rubyst way of iterating throug=
h
> >>> them, and I ask for your help in finding it. Thank you in advance!
> >> I am not sure I understand exactly what you are trying to do. =A0Does =
this
> >> help?
>
> >> irb(main):005:0> r =3D '01' .. '10'
> >> =3D> "01".."10"
> >> irb(main):006:0> r.zip(r){|xx,yy| puts "aa#{xx}bb#{yy}"}
> >> aa01bb01
> >> aa02bb02
> >> aa03bb03
> >> aa04bb04
> >> aa05bb05
> >> aa06bb06
> >> aa07bb07
> >> aa08bb08
> >> aa09bb09
> >> aa10bb10
> >> =3D> nil
> >> irb(main):007:0>
>
> > Thank you, Robert! it is a begining, but I need somethink like:
> > =A0aa01bb01
> > =A0aa01bb02
> > =A0aa01bb03
> > =A0aa01bb04
> > .
> > .
> > .
>
> > =A0aa02bb01
> > =A0aa02bb02
> > =A0aa02bb03
> > .
> > .
> > =A0aa10bb09
> > =A0aa10bb10
> > Can you help?
>
> Where's the difference?
>
> =A0 =A0 =A0 =A0 robert
>
> --
> remember.guy do |as, often| as.you_can - without endhttp://blog.rubybestp=
ractices.com/

The difference is that I have to iterate through yy for a given xx.
xx=3D'01', yy=3D'01'..'10', so I have 100 outputs, not only 10.