Robert Klemme wrote:
> 
> IMHO this solution is even simpler because it does not need the method:
> 
> h = Hash.new {|h,k| h[k] = Hash.new(&h.default_proc)}

Robert - I agree. I like this one better. Feels a little more ruby-ish.
Is there a way to use Proc (or whatever does work) to save this block 
and reuse it when creating a new hash ?
Something like :
a = Proc.new {|h,k| h[k] = Hash.new(&h.default_proc)}
b = Hash.new a

Note, I know this is wrong.. It'll just put the proc as the default 
value, instead of triggering the proc.
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