I'm doing this as a learning experiment. I would have thought that
since self inside method one is an object, then two inside one would
be defined on the object, not on the class.

Phlip's explanation made it clear to me though. It's as if I opened
the class and redefined two, correct?

On Feb 5, 10:26 ¨Âí¬ Êõìéáî Ìåöéóôïî ¼êõì®®®Àãïòåôåãè®îåô®áõ¾ ÷òïôåº
> What happens when you call the one method is it redefines the two > INSTANCE METHOD at the class level (ie the context of instance method > definition in the class), which means ALL objects are affected.
>
> Why would you want to do this?
>
> Julian.
>
> On 06/02/2009, at 2:05 PM, Daly wrote:
>
> > Hello all,
>
> > If I have a class such as:
>
> > class Example
>
> >  ¨Âåæ ïî> >  ¨Âõô¢ïîå>
> >  ¨Âåæ ô÷> >  ¨Âõô¢ô÷ï éîóéäå ïîå¢
> >  ¨Âîä
> >  ¨Âîä
>
> >  ¨Âåæ ô÷> >  ¨Âõô¢ô÷ï éîóéäå Åøáíðìå¢
> >  ¨Âîä
>
> > end
>
> > And I do:
> > e = Example.new
> > e.one
> > e.two
>
> > I get, obviously:
> > one
> > two inside one
>
> > What I don't understand is that if after that I do:
> > f = Example.new
> > f.two
>
> > I still get:
> > two inside one
>
> > Since the two method in question is defined within one, doesn't it
> > behave like a method on the object e? How can it override the two
> > method outside for the f object?
>
> > Thanks for your help in explaining this.
>
>