Hi all, This is just a basic parsing question, really. I'm trying to work out how I would process a URL such as "http://www.example.com/x/y/z/myfile.txt" and get back the filename "myfile". Basically the pattern is to get the past part of the string after the final /, and then strip off the filetype. Any help would be much appreciated, Thanks! Sam -- Posted via http://www.ruby-forum.com/.