```Wow!it helps a lot

"b", "c", "d" is "one" character
they combine in order

array s = ["aaa", "b", "c", "d", "ee", "f"]

the rule 3 result will be "bc" "cd" "bcd"

> Richard Zenn wrote:
>
>> Here is an array s = ["aaa", "b", "c", "d", "ee", "f"]
>> I want to combine them with some rules
>>
>> 1.
>> s[i].size > s[i+1].size
>> combine them
>> 2.
>> s[i+1].size > s[i].size
>> combine them
>> 3.
>> s[i].size + s[i+1].size
>>
>> The upper result is
>>
>> {"aaab"}
>> {"bc"}
>> {"bcd"}
>> {"cd"}
>> {"dee"}
>> {"eef"}
>
> In the first place, it seems that rules 1 and 2 combine to just say that
> they should not be equal in size.
>
> In the second place, if I read the rules correctly, they say that the
> result you want is not correct.
>
> Note:  I am assuming that rule 3 is not a rule as much as it is an
> example of how they should be combined.
>
> s = ["aaa", "b", "c", "d", "ee", "f"]
> arr = Array.new
> 0.upto(s.length - 2) { |i|
>   arr << s[i] + s[i+1] unless s[i].size == s[i+1].size
> }
> p arr
>
> => ["aaab", "dee", "eef"]
>
> "b", "c", "d" are all the same size and would be excluded by the rules.
> Could you clarify?  I must be missing something.

--
Posted via http://www.ruby-forum.com/.

```