```Hi --

On Tue, 13 May 2008, Robert Klemme wrote:

> 2008/5/13 Rob Biedenharn <Rob / agileconsultingllc.com>:
>>
>>
>>  On May 13, 2008, at 7:26 AM, Robert Klemme wrote:
>>
>>
>>> 2008/5/12 Sebastian Hungerecker <sepp2k / googlemail.com>:
>>>
>>>>
>>>>> Let's say I have:
>>>>> x=1234
>>>>> How can I convert that to the follow array:
>>>>> x=[1, 2, 3, 4]
>>>>>
>>>>
>>>> A solution that doesn't use strings:
>>>>
>>>> result_array = []
>>>> while x > 0
>>>>  result_array.unshift x % 10
>>>>  x /= 10
>>>> end
>>>> result_array
>>>>
>>>> This will "destroy" x, though.
>>>>
>>>
>>> Well, that's easily fixed: just work with another variable.  You can
>>> also combine division and mod:
>>>
>>> def int_split(x)
>>>  r = []
>>>  y = x
>>>  while y > 0
>>>   y, b = y.divmod 10
>>>   r.unshift b
>>>  end
>>>  r
>>> end
>>>
>>> Kind regards
>>>
>>> robert
>>>
>>> -- use.inject do |as, often| as.you_can - without end
>>>
>>
>>  def int_split(x)
>>   return [0] if x.zero?
>>   r = []
>>
>>   while x > 0
>>     x, b = x.divmod 10
>>     r.unshift b
>>   end
>>   r
>>  end
>>
>>  You don't need y since Fixnums are immediate.
>
> The reasoning is wrong but comes to the right conclusion: if you want
> to retain the original value of x then it does not matter whether
> values are mutable or not. It is sufficient to assign to x to loose
> the original value.
>
> In my code I don't need y because x is a method parameter.  My remark
> was a reaction to Sebastian's comment and piece of code which modified
> x.

I still like scanf :-)

David

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