Hi, globalrev wrote: > ty all for the help. haesob park did what iw anted. > > this is the program i wrote, it is an encrypter/decrypter for the > robbers language(rvarsprket in swedish), its from the book Kalle > Blomkvist by late and very famous author Astrid Lindgren. > you add o + the consonant, nothing is done to vowels. > so d becomes dod, a is just a. > > dad is therefore dodadod, super is sosupoperor etc. > > > > puts "Enter sentence to encrypt: " > str = gets > > enc = "" > for x in (0..str.length()-1) > if str[x].chr =~ /[qwrtpsdfghjklzxcvbnm]/ > enc = enc + str[x].chr + "o" + str[x].chr > else > enc = enc +str[x].chr > end > end > > print enc > > > > puts "Enter code to decrypt: " > code = gets > > x = 0 > dec = "" > while (x<code.length()) > dec = dec + code[x].chr > if code[x].chr =~ /[qwrtpsdfghjklzxcvbnm]/ > x = x + 2 > end > x = x + 1 > end > > print dec > > > > i then changed to !~ just like haesob said but if i do /aeiouy / it > doesnt react to space " ". how do i get it to treat " " as "a"? You can do with like this: if str[x].chr !~ /[\saeiouy]/ BTW, your encryption equals to str.gsub(/([^\saeiouy])/,"\\1o\\1") Regards, Park Heesob -- Posted via http://www.ruby-forum.com/.