On Apr 18, 2008, at 12:20 PM, Erik Veenstra wrote:
> If i isn't defined outside the loop, you don't have to pas i to
> the thread, so "Thread.new{" will do. However, if i is defined
> outside the loop (which it isn't, in your code...),
> "Thread.new(i){|i|" won't work (see below): It's better to use
> "Thread.new(i1){|i2|" instead.

indeed - left over from a previous iteration.

a @ http://codeforpeople.com/
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