ara.t.howard wrote:
> On Apr 4, 2008, at 8:38 AM, Rob Redmon wrote:
>> Hi,
>>
>> What's the "ruby way" to go from a date/time format that is "Year
>> Day_of_Year time" to "Year Month Day".  E.g. I want to convert
>> year=2008, day_of_year=095, frequently represented as "2008-095" to  
>> it's
>> more usual format "2008-04-04".  I've been playing with the Time class
>> and it's methods and found nifty ways to get yday, e.g.
>> Time.now.utc.yday, but how do I easily go backwards w/o writing my own
>> simple converter?
> 
>> R
> 
> 
> hi rob-
> 
> james example is good - you might find this method quite useful with
> julian days to:
> 
>    p Date.ordinal(2008,1).ctime  #=> "Tue Jan  1 00:00:00 2008"
> 
> cheers
> 
> a @ http://codeforpeople.com/


Wicked, thanks Ara!

Caution to the wind; I'm building my own 1.8.6 to experiment with.

Rob
-- 
Posted via http://www.ruby-forum.com/.