Gary Wright [2008-01-28 21:07]:
> This works for a two-level hash, which is what the OP needed.
> 
> If you want an infinite-level hash:
> 
> lazy = lambda { |h,k| h[k] = Hash.new(&lazy) }
> 
> h = Hash.new(&lazy)
you can even do it like this:

  h = Hash.new { |l, k| l[k] = Hash.new(&l.default_proc) }

;-)

> h[1][2][3][4] = 5
> 
> p h     # {1=>{2=>{3=>{4=>5}}}}

cheers
jens

-- 
Jens Wille, Dipl.-Bibl. (FH)
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