George wrote:
> What would you expect this to do?
>
> =A0 [].last =3D 1

The same thing as "[][-1] =3D 1", I'd imagine.
The problem I'm seeing would be this: If you allow arr.last =3D x, you'd al=
so=20
have to allow arr.last(n) =3D x if you want to be consistent, but that's no=
t=20
syntactically possible.


=2D-=20
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