Hi again,
I need to parse a line like this here:

       myoverlook://thatstrue@blablabla

I need at the end just thatstrue. So I wrote for the beginning:

      result = overlook.scan(/myoverlook://(.+?)\n/m)

Of course this doesn't work because of the // which are special charachters in a regexpr. But how can I tell that they shoudln't be treated as specialcharachters? Is there an escape charachter? I tried it so:

      result = overlook.scan(/myoverlook:\/\/\(.+?)\n/m)

but this throws an error:  unmatched ): /myoverlook:\/\/\(.+?)\n/

What's the correct synthax for this?

bye
-- 
kazaam <kazaam / oleco.net>