On 10/1/07, Simon Schuster <significants / gmail.com> wrote:
> a is an array. I'm trying to chop the first and last third off. or,
> choose only the middle third. can be a rough third.
>
> a.length                                       # 4808
> range = a.length * 0.3                    # 1442.4
> range = range.to_i                         # 1442
> rangetop = a.length / 2 + range       # 3846
> rangebottom = a.length / 2 - range  # 962
>
> a[rangebottom..rangetop].length     # 2885
>
>

That's a very rough third :)

arr = (1..100).to_a
bot = arr.length/3
p arr[bot..bot*2]

[34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50,
51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67]

Harry

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