Ben Bleything wrote: > On Tue, Sep 04, 2007, Cd Cd wrote: >> 'b' will print out the body of the web page. So 'b' in this case would >> be become the receiver (ie imgs = b.scan(/<img src="(.*?)"/m)), then we >> go from getting the value 'b' (via p b) to 'b' acting like a method >> (via imgs = b.scan(/<img src="(.*?)"/m))? > > b is an object in either case. When you 'p b', you're printing out the > contents of the b object... when you call b.scan, you're calling scan on > the b object. > > Make more sense? > > Ben Yes it does. -- Posted via http://www.ruby-forum.com/.