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Two quiz solutions here - one as per my interview situation, and one
for golfing.

On 6/3/07, darren kirby <bulliver / badcomputer.org> wrote:
> So: much like Marcel Proust biting into a madelaine, when I read this quiz on
> Friday I had a rush of old memories. I have never heard of fizzbuzz being
> used as a recruitment technique before, however, I am familiar with it
> because back in high school we played it as a drinking game. If we were
> feeling particularly hardcore we would also add in 'Bang' for multiples of 7.
> over twelve years or so...
>
> Anyway, I have deviated from the official spec in a few ways here. First of
> all, I saw no reason to stop at 100, so my solution will print results for
> any user-specified 'n'. Rather than golfing, which I am no good at, I decided
> to go with an obvious solution.
>
> The second deviation is that because the solution is fairly short (ie: about a
> paragraph) I thought it would be interesting to write solutions in a few
> other languages as a point of comparison. To that end I also wrote solutions
> in Python, Lua, Scheme, and plain old C. Hopefully you can forgive me some
> off-topicness for posting these as well.
>
> On with the code:
>
> # fizz.rb
> 1.upto(ARGV[0].to_i) do |n|
>   if n % 15 0
>     print "FizzBuzz "
>   elsif n % 5 0
>     print "Buzz "
>   elsif n % 3 0
>     print "Fizz "
>   else print "#{n} "
>   end
> end
> puts
>
> # fizz.py
> import sys
> for n in range(1,int(sys.argv[1])+1):
>     if n % 15 0:
>         sys.stdout.write("FizzBuzz ")
>     elif n % 3 0:
>         sys.stdout.write("Fizz ")
>     elif n % 5 0:
>         sys.stdout.write("Buzz ")
>     else: sys.stdout.write("%i " % n)
> print
>
> -- fizz.lua
> for narg[1] do
>   if n % 15 0 then
>     io.write("FizzBuzz ")
>   elseif n % 3 0 then
>     io.write("Fizz ")
>   elseif n % 5 0 then
>     io.write("Buzz ")
>   else
>     io.write(n .. " ")
>   end
> end
> print()
>
> /* fizz.c */
> #include <stdio.h>
>
> int main(int argc, char *argv[]) {
>     int i;
>     for (i  ; i < toi(argv[1]); i++) {
>         if (i % 15 0)
>             printf("%s ", "FizzBuzz");
>         else if (i % 3 0)
>             printf("%s ", "Fizz");
>         else if (i % 5 0)
>             printf("%s ", "Buzz");
>         else
>             printf("%i ", i);
>     }
>     printf("\n");
>     return 0;
> }
>
> ;;; fizz.scm
> (define (fizz x)
>   (define (mod5? n)
>     (if (eq? (modulo n 5) 0) #t #f))
>   (define (mod3? n)
>     (if (eq? (modulo n 3) 0) #t #f))
>   (define (fizz-iter n x)
>      (cond
>        ((> n x) (newline) #t)
>        ((and (mod3? n) (not (mod5? n))) (display "Fizz ")
>           (fizz-iter (+ n 1) x))
>        ((and (mod5? n) (not (mod3? n))) (display "Buzz ")
>           (fizz-iter (+ n 1) x))
>        ((and (mod5? n) (mod3? n)) (display "FizzBuzz ")
>           (fizz-iter (+ n 1) x))
>        (else (display n) (display " ")
>           (fizz-iter (+ n 1) x))))
>   (fizz-iter 1 x))
>
> cheers,
> -d
> --
> darren kirby :: Part of the problem since 1976 :: http://badcomputer.org
> "...the number of UNIX installations has grown to 10, with more expected..."
> - Dennis Ritchie and Ken Thompson, June 1972
>
>

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