Here are my solutions to Quiz 126.  Because it was the one that  
popped into my mind when I read the quiz description, the first is  
the one that I think I'd produce if challenged during a job interview.

<code>
# Simple, obvious (to me) way to do it.
(1..100).each do |n|
    case
    when n % 15 == 0 : puts 'FizzBuzz'
    when n % 5 == 0  : puts 'Buzz'
    when n % 3 == 0  : puts 'Fizz'
    else puts n
    end
end

# Not quite so obvious, but a little DRYer:
(1..100).each do |n|
    puts  case
          when n % 15 == 0 : 'FizzBuzz'
          when n % 5 == 0  : 'Buzz'
          when n % 3 == 0  : 'Fizz'
          else n
          end
end

# Of course, could do it with if-elsif-else ...
(1..100).each do |n|
    puts(
       if n % 15 == 0
          'FizzBuzz'
       elsif n % 5 == 0
          'Buzz'
       elsif n % 3 == 0
          'Fizz'
       else n
       end
    )
end

# ... or even with the ternary operator.
(1..100).each do |n|
    puts(
       n % 15 == 0 ? 'FizzBuzz' :
       n % 5 == 0  ? 'Buzz' :
       n % 3 == 0  ? 'Fizz' : n
    )
end
</code>

Regards, Morton