Well, It's a few minutes early, but I've got an early morning tomorrow.

Here's three attempts from me.

First is my initial shot, which will cause many of you to cringe at  
the use of nested ternary operators...
Second, I decided to mess with Fixnum.
Then I got a little bored and thought of something for our friends at  
thedailywtf (still can't take to the new name)

I'm willing to go with whoever suggested this might bring in the  
largest number of RubyQuiz responses yet.

Cheers,
Dave

#-------------------------------------------------
#Quick first attempt

1.upto(100) {|i| puts(i%15==0 ? 'FizzBuzz' : i%5==0 ? 'Buzz' : i% 
3==0 ? 'Fizz' : i)}


#-------------------------------------------------
#Lets play with Fixnum

class Fixnum
   def fizz_buzzed
     a= (self%3==0 ? 'Fizz' : "")
     a+= 'Buzz' if self%5==0
     a= self.to_s if a==""
     a
   end
end

1.upto(100) {|i| puts i.fizz_buzzed}


#-------------------------------------------------
# How about something for thedailywtf.com?

def divisible_by_3(i)
   if i.to_s.size>1 then
     divisible_by_3(i.to_s.split(//).map{|char| char.to_i}.inject{| 
a,b| a+b})
   else
     [3,6,9].include?(i)
   end
end

def divisible_by_5(i)
   ['0','5'].include?(i.to_s[-1].chr)
end

def divisible_by_15(i)
   divisible_by_3(i) && divisible_by_5(i)
end


1..100.each do |i|
    if divisible_by_15(i) then puts 'FizzBuzz'
    elsif divisible_by_3(i) then puts 'Fizz'
    elsif divisible_by_5(i) then puts 'Buzz'
    else puts i
    end
end