```Hi thank you both :)

I took Tim's answer because it's faster and much smaller and my loop had
some timeout-problems with the case-when method to solve it.

Tim Hunter wrote:
> anansi wrote:
>> Hi,
>> I'm struggeling with writing a little script. It has a loop just e.g.
>> like this:
>>
>> for x in 1..10 do
>> begin
>>  puts "#{x}"
>> end
>>
>> The userinput is the loop count (so above the userinput would have
>> been 1..10): but now this userinput can be a fixnum like 12 or 36 or
>> it can be a range like 1..10 or 24..84 or an array like [23,41,35,63]
>> and for every 3 different input kinds the loop shall do the same.
>>
>> Like in this example:
>>
>> If userinput is just fixnum 11 it just prints 11 on the screen, is it
>> a range from 1..10 all numbers from 1..10 shall be printed and for an
>> array all single numbers stored in the array...you know what I mean.
>> The actual routine doesn't print anything it's just about I have to
>> process numbers which can the user give in, in three different ways
>> and I was wondering if it is possible to build this into one single
>> loop and not three different ones?
>>
>
> Assuming that userinput can only be a Range, Array, or Fixnum...both
> Range and Array have an each method. Test userinput to see if it
> responds to :each. If it does, you're golden. If it doesn't, it's a
> Fixnum. Make an array from the Fixnum by calling Array(). Now iterate
> over the result using :each. (This is untested but it'll give you an
> idea of what to do.)
>
> userinput = Array(userinput) unless userinput.respond_to? :each
> userinput.each do |x|
>    puts x
> end
>
>
> P.S. the puts method converts its argument to a string. You don't need
> to use "#{x}".

--
greets

(
)
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one must still have chaos in oneself to be able to give birth to a
dancing star

```