```On 06.05.2007 15:20, anansi wrote:
> Hi,
> I'm struggeling with writing a little script. It has a loop just e.g.
> like this:
>
> for x in 1..10 do
> begin
>  puts "#{x}"
> end
>
> The userinput is the loop count (so above the userinput would have been
> 1..10): but now this userinput can be a fixnum like 12 or 36 or it can
> be a range like 1..10 or 24..84 or an array like [23,41,35,63] and for
> every 3 different input kinds the loop shall do the same.
>
> Like in this example:
>
> If userinput is just fixnum 11 it just prints 11 on the screen, is it a
> range from 1..10 all numbers from 1..10 shall be printed and for an
> array all single numbers stored in the array...you know what I mean. The
> actual routine doesn't print anything it's just about I have to process
> numbers which can the user give in, in three different ways and I was
> wondering if it is possible to build this into one single loop and not
> three different ones?

def my_loop(x,&b)
case x
when /\A\d+\z/
x.to_i.times(&b)
when /\A(\d+)\.\.(\d+)\z/
(\$1.to_i .. \$2.to_i).each(&b)
when /\A\[\s*\d+\s*(?:,\s*\d+\s*)*\]\z/
eval(x).each(&b)
else
raise ArgumentError, "Don't know what to do with: #{x}"
end
end

>> my_loop("5") {|x| p x}
0
1
2
3
4
=> 5
>> my_loop("1..5") {|x| p x}
1
2
3
4
5
=> 1..5
>> my_loop("[5,3,2]") {|x| p x}
5
3
2
=> [5, 3, 2]
>> my_loop("1,2") {|x| p x}
ArgumentError: Don't know what to do with: 1,2
from (irb):10:in `my_loop'
from (irb):16
from :0
>>

Kind regards

robert

```