Hi,

On Tuesday 13 February 2007 07:29, Edwin Fine wrote:
> Incidentally, the reason why lambda {} == lambda {} may be because all
> the values I showed in the previous post (e.g. data->body, data->var,
> etc) are all zero or NULL (no vars, no body, and so on) which would make
> them equal and therefore the procs equal.

Thank you for your insight! It's clear now. /me has to remember to always take 
a look at the source. :).

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