On Thu, 25 Jan 2007, John Kopanas wrote:

> I have the following:
>
> a = (y != 0) ? (x/y) : 0
>
> There must be a sexier way of doing this!  Any suggestions?
>
> On a side note... how do we do exception handling on the same line as 
> statement?
>
> a = x/y rescue 0
>
> That does not work but does it make sense?  Is it because dividing by
> zero does not throw an exception?
>
> Thanks for your help! :-)
>

works for me?

   harp:~ > ruby -e'  a = 42/0 rescue 42;  p a  '
   42

i think you're doing the right thing with

> a = x/y rescue 0

how doesn't it work?

regards.

-a
-- 
we can deny everything, except that we have the possibility of being better.
simply reflect on that.
- the dalai lama