On Mon, 22 Jan 2007, Robert MannI wrote:

> I am wondering if the mighty ruby crowd has a brilliant idea for a tricky
> problem I am solving.
> hsh['a']['b']['c'] = {}
>
> Is there an elegant solution to this, without maybe looping or eval'ing too
> much?

I suspect you are asking the wrong question.

My experience is that if you tell the Mighty Ruby Crowd why you wanted
to do that, they tend to come up with a surprisingly more elegant
thing to be doing, complete with a really quite simple way of doing it.


John Carter                             Phone : (64)(3) 358 6639
Tait Electronics                        Fax   : (64)(3) 359 4632
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