9 digits in a string "123456789", convert to individual Fixnums 
[1,2,3,4,5,6,7,8,9], or as below

a, b, c, d, e, f, g, h, i = id.scan(/\d/).map(&:to_i)

Simpler yet how about ["1", "2", ...]. Is scan the only direct way?

I tried the "*" mechanism, no such luck, and tried array slicing again 
no luck.  TIA
-- 
John Pywtorak
Cal Poly State University
ITS/ASAS
805-756-5906