```Kevin Olbrich wrote:
> James Gray wrote:
>> On May 27, 2006, at 7:36 AM, Kevin Olbrich wrote:
>>
>>> Here's a simple problem that seems like a good Ruby exercise.
>>>
>>> Given a string containing an Excel-like range specifier like this:
>>> "C5:E8", generate an array of all the cells in the array.
>>>
>>> In this case, the output should be something like this....
>>>
>>> ["C5", "C6", "C7", "C8", "D5", "D6", "D7", "D8", "E5", "E6", "E7",
>>> "E8"]
>>
>>  >> cell_range = "C5:E8"
>> => "C5:E8"
>>  >> from, to = cell_range.split(":")
>> => ["C5", "E8"]
>>  >> cells = (from[/[A-Z]+/]..to[/[A-Z]+/]).map do |col|
>> ?>   (from[/\d+/]..to[/\d+/]).map { |row| col + row }
>>  >> end.flatten
>> => ["C5", "C6", "C7", "C8", "D5", "D6", "D7", "D8", "E5", "E6", "E7",
>> "E8"]
>>
>> James Edward Gray II
>
> James' solution gets points for style, but a's is the most complete.
>
> Good stuff guys, I always learn some good ruby fu from this list.
>
> _Kevin

Here's a variation of James' solution that covers the other cases and is
a bit more robust (i.e., it works if the columns are lowercase, and if
you specify the range backwards..

def excelrange(r)
from, to = r.upcase.split(":").sort
begin
cells = (from[/[A-Z]+/]..to[/[A-Z]+/]).map do |col|
(from[/\d+/]..to[/\d+/]).map { |row| col + row }
end.flatten
rescue
cells = (from..to).to_a
end
end

excelrange("A4:B6") => ["A4", "A5","A6","B4","B5","B6"]
excelrange("B6:A4") => ["A4", "A5","A6","B4","B5","B6"]
excelrange("4:6") => ["4","5","6"]
excelrange("A:B") => ["A","B"]

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```