Run with "C5:E8" it results in this:

["C5", "C6", "C7", "C8", "C9", "D0", "D1", "D2", "D3", "D4", "D5",
"D6", "D7", "D8", "D9", "E0", "E1", "E2", "E3", "E4", "E5", "E6",
"E7", "E8"]

Not the expected:

["C5", "C6", "C7", "C8", "D5", "D6", "D7", "D8", "E5", "E6", "E7", "E8"]

On 5/27/06, Takumi Kimoto <peerler / gmail.com> wrote:
> How about this one?
>
> r="A1:C5".split(':')
> (r[0]..r[1]).to_a
>
>
> --
> Takumi Kimoto <peerler / gmail.com>
>
>