On 3-May-06, at 6:44 PM, Matt Bauer wrote:

> What is the easiest way to convert a hex value like:
>
> 0x000000000000F03F (big endian, IEEE754)
>
> to a Float in Ruby?
>
> Thanks,
> Matt
>
> --  
> Posted via http://www.ruby-forum.com/.
>
>

Probably using pack and unpack, my first guess is something like

irb(main):001:0> [0x000000000000F03F].pack('Q').unpack('G')
=> [3.03865194161742e-319]


but now I have to look up IEEE and it looks reasonable:

irb(main):002:0> [0x0000000000000000].pack('Q').unpack('G')
=> [0.0]
irb(main):003:0> [0x8000000000000000].pack('Q').unpack('G')
=> [-0.0]

and using a sample single precision number in binary from http:// 
www.psc.edu/general/software/packages/ieee/ieee.html

0 10000001 10100000000000000000000 = +1 * 2**(129-127) * 1.101 = 6.5

irb(main):005:0> [0b01000000110100000000000000000000].pack('L').unpack 
('g')
=> [6.5]

Hope this helps,

Mike

-- 

Mike Stok <mike / stok.ca>
http://www.stok.ca/~mike/

The "`Stok' disclaimers" apply.