> But with division,
> 
> 2*3 = 6
> 6/3 = 2
> 6*2 = 2, therefore (1/3) = 2 and 2 = 1 (since it's the identity.)

because 6/3 = 6*1/3 and 6*2 = 6*1*2 ?
But! you can not just mid-way-divide by 6...
1/6 = x mod 10, which, oh horror, does not exist!!!

+--- Kero ------------------------------ kero / chello.nl ---+
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