On Jan 26, 2006, at 4:55 PM, Jon Baer wrote:

> Nice .. well that works :-) but in the constructor can you tell me  
> what "*" would literally "mean"?

I see you've already got this answer.

> Does this just take only an Array obj or could you place any object  
> in there w/ public attributes/methods?

I'm not sure what "this" refers to in the above sentence.  Try asking  
your question again, please.

> (Was this covered in pick-axe somewhere I missed?)

I just looked an can't seem to find it.  It's the opposite of the *  
operator described on page 347 (explodes an Array out, instead of  
collecting it in).

James Edward Gray II