Hi -- On Tue, 10 Jan 2006, Sam Dela Cruz wrote: > I got different results in Perl and Ruby of this regular expression. Can > somebody maybe give me a "Ruby Way" solution of this? The output from > Perl is what I want. But I'm currently programming this is Ruby. > > def transform_data(data) > if (data=~/^[\d\.]+$/) #numbers > puts "Got here!" > else > puts("'" + data + "'") > end > end > > data = "patched 3 systems: > 134.27.56.237 > 134.27.59.6 > 134.27.55.43" > > transform_data(data) > #snippet end ============ > > Output is: > Got here! > > Now why would it match in Ruby? Am I missing something here? ^ and $ match start and end of line, not string. For start and end of string, you want \A and \z (or \Z to ignore final newline). David -- David A. Black dblack / wobblini.net "Ruby for Rails", from Manning Publications, coming April 2006! http://www.manning.com/books/black