```What about

irb(main):033:0> h = {:c=>333,:b=>2, :a=>1}
=> {:c=>333, :a=>1, :b=>2}
irb(main):034:0> def foo h
irb(main):035:1>   puts "a is #{h[:a]}"
irb(main):036:1>   puts "b is #{h[:b]}"
irb(main):037:1>   puts "c is #{h[:c]}"
irb(main):038:1> end
=> nil
irb(main):039:0> foo h
a is 1
b is 2
c is 333
=> nil

> Sche Daniel wrote:
> > Hello all,
> >
> > I am looking for Ruby equivalent for this Python Code
> >
> >  >>> def foo(a,b,c):
> > ...     print "a is ", a
> > ...     print "b is ", b
> > ...     print "c is ", c
> > ...
> >  >>> h = {"c":3, "a":1, "b":2}
> >  >>>
> >  >>> foo
> > <function foo at 0x403d6f7c>
> >  >>> foo(**h)
> > a is  1
> > b is  2
> > c is  3
> >
> > my first try
> >
> > => {"c"=>333, :b=>2, :a=>1}
> > irb(main):017:0> def foo a,b,c
> > irb(main):018:1> puts "a is #{a}"
> > irb(main):019:1> puts "b is #{b}"
> > irb(main):020:1> puts "c is #{c}"
> > irb(main):021:1> end
> > => nil
> > irb(main):022:0> foo *h
> > a is c333
> > b is b2
> > c is a1
> > => nil
> >
> >
> > this seem to replace (or substituate) the parameters expected by foo
> > in the order of hash. And since hash has no order (in both languages)
> > it's a random replacement.
> >
> > Is there a trick I don't know about?

```