Morus Walter a ñÄrit :
> In article <20060106185354.LPAB613.centrmmtao03.cox.net / localhost.localdomain>,
> 	Ruby Quiz <james / grayproductions.net> writes:
> 
>>Or, for something more complicated:
>>
>>	> roll.rb "(5d5-4)d(16/d4)+3"
>>	31
> 
> 
> What's the execution order in this case?
> Do 5d5-4 rolls with 5d5-4 probably different dices having 16/d4 sides 
> (number of sides calculated for each roll individually) or should one
> choose the number of sides once for all rolls?
> I guess it doesn't make much difference but it should be specified...
> 
> Morus

IMO, all the parenthesis must be resolved before going further.
Thus in the example you rool :
5d5
1d4
and the last one with the result of the two computations.

Otherwise, it would be impraticle to do that with real dices (mmmmhh ...)

Pierre