On 9/2/05, Simon Kröçer <SimonKroeger / gmx.de> wrote:
> s1 = ['this', 'is', 'a', 'test'].join("\n")
> s2 = ['this', 'is', 'the', 'test'].join("\n")
> 
> (0...s1.size).inject(1) do |l, i|
>    puts "difference on line: #{l}" or break if s1[i] != s2[i]
>    l = (s1[i] == 10) ? l+1 : l
> end

What's the second to last line for?

  l = (s1[i] == 10) ? l+1 : l

That will always return false (since s1[i] is always a string, and
string/integer comparison is always false), so your line count will
always be 1.

Jacob Fugal