Brock Weaver wrote:
> DeMorgan's theorem and operator precedence in ruby.
> 
> DeMorgan's theorem in a nutshell:
> 
> (Not A) and (Not B) == Not (A or B)
> 
> Your code is
> 
> (Not A) and (Not B) == (Not A) or (B)
> 
> See the difference?
> 

Yep, thank you for the quick response!

Zach