```David A. Black wrote:

> Hi --
>
> On Sat, 21 May 2005, Luca Pireddu wrote:
>
>> David A. Black wrote:
>>
>>> Hi --
>>>
>>> On Sat, 21 May 2005, Eric Mahurin wrote:
>>>
>>>
>>> It's hard, I find, to come up with an exact description of what the
>>> unarr?ay (unary unarray) operator does that fits every case.  The
>>> closest I've come is: *a = x means: a gets assigned that which, when
>>> stripped of one level of array-ness, is x.  Thus:
>>>
>>>    *a = 1,2   # [1,2] stripped of [] is 1,2 so a is [1,2]
>>>    *a = *[1,2] # a stripped of [] is [1,2] stripped of [], so
>>>                # a is [1,2]
>>>
>>>    def x(*args); end
>>>    x(1,2,3)   # [1,2,3] stripped of [] is 1,2,3, so args is [1,2,3]
>>>    x([1,2,3]) # [[1,2,3]] stripped of [] is [1,2,3], so args
>>>               # is [[1,2,3]]
>>>
>>> Then there's
>>>
>>>    a = 1,2   # automatic arraying -- the opposite of *
>>>    a = *[1,2]  # un-arraying followed by automatic arraying :-)
>>>
>>> or something like that.
>>>
>>>
>>> David
>>>
>>
>> Maybe a simpler way to look at it is *a = x means a = [x], or simply
>> enclose the rhs in an array before assignment.
>
> I'm not sure how that's different from what I was saying above.  Or
> did you mean a simpler way to say it? :-)
>
>
> David
>

Hello.  Yes, I wasn't trying to correct you.  Just suggesting a simpler way of
saying the same thing :-)

Luca

```