"Meino Christian Cramer" <Meino.Cramer / gmx.de> schrieb im Newsbeitrag
news:20040705.091922.03982506.Meino.Cramer / gmx.de...
> From: "Gavin Sinclair" <gsinclair / soyabean.com.au>
> Subject: Re: Transforming...
> Date: Mon, 5 Jul 2004 16:07:19 +0900
>
> Hi Gavin,
>
>  whow! what a fast reply ! Thank you very much ! :)
>
>  I want an algorithm, which when applied like this
>
>    b=<algo>
>
>  it does the same as I would do this by hand:
>
>
b=[[<val1>,<val2>,<val3>],[<val4>,<val5>,<val6>],[<val7>,<val8>,<val9>]]

That's exactly what Gavin gave you.  What are you after?

    robert

>
>
>
> > Meino wrote:
> >
> > >  In my program there is a hash of this form
> > >
> > >    a={ "<string_a>" => [<val1>,<val2>,<val3>],
> > >    "<string_b>" => [<val4>,<val5>,<val6>],
> > >    "<string_c>" => [<val7>,<val8>,<val9>]
> > >    }
> > >
> > >   I am looking for a short and handy way to produce an array out of
> > > this, which looks like:
> > >
> > >
b=[[<val1>,<val2>,<val3>],[<val4>,<val5>,<val6>],[<val7>,<val8>,<val9>]]
> > >
> > >  without iterating over the hash.
> >
> > I presume you mean you just want an array of the *values* in the hash?
> >
> >   b = a.values
> >
> > If you want the values sorted according to the order of the keys:
> >
> >   b = a.keys.sort.map { |k| a[k] }
> >
> > Cheers,
> > Gavin
> >
> >
> >
> >
> >
>
>