Hi,

At Fri, 4 Jun 2004 00:06:07 +0900,
Austin Ziegler wrote in [ruby-talk:102289]:
> Where will the ** notation fit in? Will it be:
> 
>   foo(** :foo => 14, :bar => 92)
>   foo(**{ :foo => 14, :bar => 92 })

As well as *array, it prefixes an expression.  So the former
wouldn't be valid syntax.

> And this will effectively make one of those two:
> 
> > foo(foo: 14, bar: 92)
> 
> ?

AFAIK, it will.

-- 
Nobu Nakada