Issue #16100 has been updated by prebsch (Patrick Rebsch).


Thanks for the explanation, Jeremy. I *think* I understand now. I took a look at the source and made another example to help me understand. I see now that the inconsistency only arises with the argument-less call of the visibility modifier.

```ruby
def test_private_visibility(klass, method_name)
  puts
  puts "Case: #{ klass } ##{ method_name } is private?"
  puts "  #=> #{ klass.private_instance_methods.include?(method_name) }"
end

class Parent
  def self.private(*)
    puts "::private called from #{ self.name }"
    super
  end
end

class Child_1 < Parent
  private
  def child_instance_method; end
end

class Child_2 < Parent
  def child_instance_method; end
  private(:child_instance_method)
end

test_private_visibility(Child_1, :child_instance_method)
test_private_visibility(Child_2, :child_instance_method)
```

```
::private called from Child_1
::private called from Child_2

Case: Child_1 #child_instance_method is private?
  #=> false

Case: Child_2 #child_instance_method is private?
  #=> true
```

The source code makes it clear that the argument-less version is dependent upon a scope. So if I understand you correctly, the call to `super` in `Parent` is what would be calling this, and since that is in the scope of `Parent`, the originating call from `Child_1` doesn't work because the scope doesn't match?

```c
static VALUE
set_visibility(int argc, const VALUE *argv, VALUE module, rb_method_visibility_t visi)
{
    if (argc == 0) {
        rb_scope_visibility_set(visi);
    }
    else {
        set_method_visibility(module, argc, argv, visi);
    }
    return module;
}
```

----------------------------------------
Bug #16100: Visibility modifiers don't call super correctly when overridden in alternative ways
https://bugs.ruby-lang.org/issues/16100#change-80813

* Author: prebsch (Patrick Rebsch)
* Status: Open
* Priority: Normal
* Assignee: 
* Target version: 
* ruby -v: ruby 2.7.0dev (2019-08-14) [x86_64-darwin18]
* Backport: 2.5: UNKNOWN, 2.6: UNKNOWN
----------------------------------------
It seems that the method visibility modifiers don't call `super` correctly when they are overridden in certain ways. I expected the following examples to all behave the same since they are all being defined on the singleton class, but only the first operates correctly presumably because it is explicitly defined on the singleton class. I've reproduced this behavior with `2.7.0`, `2.6.3`, and `2.5.5`.

``` ruby
def test_visibility(description, klass)
  puts "Case: #{ description }"
  puts "  #=> #{ klass.private_instance_methods.include?(:private_method) }"
  puts
end

test_visibility('explicit', Class.new {
  def self.private(*); super; end
  private; def private_method; end
})

test_visibility('opened singleton', Class.new {
  class << self
    def private(*); super; end
  end
  private; def private_method; end
})

test_visibility('include/prepend to singleton', Class.new {
  module M
    def private(*); super; end
  end
  singleton_class.prepend(M)
  private; def private_method; end
})
```

```
Case: explicit
  #=> true

Case: opened singleton
  #=> false

Case: include/prepend to singleton
  #=> false
```




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