Issue #12717 has been updated by marcandre (Marc-Andre Lafortune).


I believe this is as designed.

As I stated previously (https://bugs.ruby-lang.org/issues/11967#note-3), my understanding is that:

* after all mandatory unnamed arguments are filled
* if the last remaining argument is hash-like
* and all its keys are symbols
* and the method called uses keyword arguments => then that parameter is used for keyword arguments.

I believe we should close this issue.

----------------------------------------
Bug #12717: Optional argument treated as kwarg
https://bugs.ruby-lang.org/issues/12717#change-73900

* Author: AMHOL (Andy Holland)
* Status: Open
* Priority: Normal
* Assignee: matz (Yukihiro Matsumoto)
* Target version: 
* ruby -v: 2.3.1
* Backport: 2.1: UNKNOWN, 2.2: UNKNOWN, 2.3: UNKNOWN
----------------------------------------
When you define a method with an optional argument and keyword arguments (whether explicitly or with options splat) the defaulted argument can not take a hash argument, instead it is interpreted as keyword arguments:

~~~ ruby
class Foo
  def self.options(value = nil, **options)
    puts value.inspect
    puts options.inspect
  end

  def self.kwarg(value = nil, kw: nil)
    puts value.inspect
    puts kw.inspect
  end

  def self.splat(*args, kw: nil)
    puts args.inspect
    puts kw.inspect
  end
end

Foo.options({})
# nil
# {}
Foo.kwarg({})
# nil
# nil
Foo.splat({})
# []
# nil

Foo.options({ key: :value })
# nil
# {:key=>:value}
Foo.kwarg({ key: :value })
# ArgumentError: unknown keyword: key
Foo.splat({ key: :value })
# ArgumentError: unknown keyword: key
~~~

I would expect the output to be:

~~~ ruby
Foo.options({})
# {}
# {}
Foo.kwarg({})
# {}
# nil
Foo.splat({})
# [{}]
# nil

Foo.options({ key: :value })
# {:key=>:value}
# {}
Foo.kwarg({ key: :value })
# {:key=>:value}
# nil
Foo.splat({ key: :value })
# [{:key=>:value}]
# nil
~~~




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