Issue #13736 has been updated by dawg (Andrew Dumke).


This does not seem to be corrected on ruby 2.4.2p198 (2017-09-14 revision 59899) [x86_64-darwin16]

Exactly the same results as before.

----------------------------------------
Bug #13736: ruby -00 should be the same as setting $/=""
https://bugs.ruby-lang.org/issues/13736#change-66841

* Author: dawg (Andrew Dumke)
* Status: Closed
* Priority: Normal
* Assignee: matz (Yukihiro Matsumoto)
* Target version: 
* ruby -v: 2.4.1p111
* Backport: 2.2: UNKNOWN, 2.3: UNKNOWN, 2.4: UNKNOWN
----------------------------------------
Suppose you have blocks of text separated by 2 or more \n. A typical text file with records defined by a black line. 

Given:

```
$ cat lines
f1, r1
f2, r1 then 2 \n:

f1, r2 then 3 \n:


f1,r3
f2,r3 then 4 \n:



f1, r4
f2,r4 then 6 \n: 





f1,r5
```

The script `$ ruby -00 -F"\n" -lane 'END{p $.}' lines` SHOULD have the same number of records as `$ ruby -F"\n" -lane 'BEGIN{$/=""}; END{p $.}' lines`. It does not not.

The script `$ ruby -00 -F"\n" -lane 'END{p $.}' lines` SHOULD have the same number of record as `$ perl -00 -F"\n" -lane 'END{print $.}' lines` Again, it does not. 

The script `$ ruby -00 -F"\n" -lane 'END{p $.}' lines` shows 8. The other scripts here show 5 -- the correct number. 

The behavior of the `-00` command switch is not the same as perl's `-00` command switch. It is also not the same as setting `$/=""` in either ruby or perl. 

The `\n\n` pattern between blocks should be a single record separator even if you have `\n\n\n\n\n` That is true in perl, awk, gawk, and ruby with `$/=""`. It is not true with `ruby -00`. This is a bug. 

---Files--------------------------------
ruby_bug.sh (1.39 KB)


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