Roger Pack wrote:
>> Then how it is different from
>> foo.bar if foo.respond_to?(:bar)
>>
>> ?
> 
> You don't have to write foo and bar twice :)
> 
> I'm with you in thinking that adding another syntax
> foo.?bar
> seems a little much when a new method will do.
> -=r

Agree on both points. But what does the new method return?

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       vjoel : Joel VanderWerf : path berkeley edu : 510 665 3407