Bug #1034: Ruby 1.8 evaluates block argument out of order from other arguments and receiver
http://redmine.ruby-lang.org/issues/show/1034

Author: Charles Nutter
Status: Open, Priority: Normal

In Ruby 1.9 and all alternative impls I tested, block arguments are evaluated in the order they're encountered in a call. For example:

a.foo(b, c, &d)

The expected order would be left to right, a, then b, then c, then d. But Ruby 1.8 evaluates in the order d, a, b, c. In a case like the following (somewhat contrived) this would have odd side effects:

x = 0
(x += 1; a).foo(x += 1, x += 1, &(x += 1, d))

In 1.8, the two non-block arguments would be 3, 4, while on Ruby 1.9 and other impls it would be 2, 3 as you'd expect.


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